Algebra one, semester one, unit five, assignment: find maximum
and minimum
Y=-x^2+50x+10
To know if a vertex is a maximum or a minimum you look at
whether the x^2 term is positive or negative. Negative is
maximum and positive is minimum. Since the number that fills
the place is negative the vertex it maximum.
To find the x coordinate of the vertex you use the formula
X=-b/2a
A=-1 b=50
X=-50÷2*-1
X=-50÷-2
X=25
To find the y coordinate of the vertex plug the number found
from the x coordinate into the function
Y=25^2+50*25+10
Y=625+1250+10
Y= 1885
(25,1885)
For this situation the vertex represents the characters path. X is
twenty five and that is the time in seconds it takes the character
to move across one parabolic path. Y is one thousand eight
hundred eighty five and that is the height of the character in
pixels.
Y=2x^2-20x+100
To know if a vertex is a maximum or minimum you look at
whether the x^2 term is positive or negative. Negative is

maximum and positive is minimum. Since the number that fills
the x^2 place is a positive number the vertex is minimum.