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boost/python/ptr.hpp

Introduction
Functions
Class template pointer_wrapper
Class template pointer_wrapper types
Class template pointer_wrapper constructors and destructor
Class template pointer_wrapper observer functions
Metafunctions
Example

<boost/python/ptr.hpp> defines the ptr() function template, which allows users to specify how to convert C++ pointer values to python in the context of implementing overridable virtual functions, invoking Python callable objects, or explicitly converting C++ objects to Python. Normally, when passing pointers to Python callbacks, the pointee is copied to ensure that the Python object never holds a dangling reference. To specify that the new Python object should merely contain a copy of a pointer p, the user can pass ptr(p) instead of passing p directly. This interface is meant to mirror the use of boost::ref(), which can be similarly used to prevent copying of referents.

ptr(p) returns an instance of pointer_wrapper<>, which can be detected using the is_pointer_wrapper<> metafunction; unwrap_pointer<> is a metafunction which extracts the original pointer type from a pointer_wrapper<>. These classes can be thought of as implementation details.

template <class T>
pointer_wrapper<T> ptr(T x);

Requires

T is a pointer type.

Returns

pointer_wrapper<T>(x)

Throws

nothing.

A "type envelope" which is returned by ptr(), used to indicate reference semantics for pointers passed to Python callbacks.

namespace boost { namespace python
{
    template<class Ptr> class pointer_wrapper
    {
     public:
        typedef Ptr type;

        explicit pointer_wrapper(Ptr x);
        operator Ptr() const;
        Ptr get() const;
    };
}}
typedef Ptr type;

The type of the pointer being wrapped.

explicit pointer_wrapper(Ptr x);

Requires

Ptr is a pointer type

Effects

Stores x in a the pointer_wrapper<>.

Throws

nothing.

operator Ptr() const;
Ptr get() const;

Returns

a copy of the stored pointer.

Rationale

pointer_wrapper is intended to be a stand-in for the actual pointer type, but sometimes it's better to have an explicit way to retrieve the pointer.

A unary metafunction whose value is true iff its argument is a pointer_wrapper<>.

namespace boost { namespace python
{
    template<class T> class is_pointer_wrapper
    {
        static unspecified value = ...;
    };
}}

Returns

true iff T is a specialization of pointer_wrapper<>. value is an integral constant convertible to bool of unspecified type

A unary metafunction which extracts the wrapped pointer type from a specialization of pointer_wrapper<>.

namespace boost { namespace python
{
    template<class T> class unwrap_pointer
    {
        typedef unspecified type;
    };
}}

Returns

T::type if T is a specialization of pointer_wrapper<>, T otherwise

This example illustrates the use of ptr() to prevent an object from being copied:

#include <boost/python/call.hpp>
#include <boost/python/ptr.hpp>

class expensive_to_copy
{
   ...
};

void pass_as_arg(expensive_to_copy* x, PyObject* f)
{
   // call the Python function f, passing a Python object built around
   // which refers to *x by-pointer.
   //
   // *** Note: ensuring that *x outlives the argument to f() is    ***
   // *** up to the user! Failure to do so could result in a crash! ***

   boost::python::call<void>(f, ptr(x));
}
...

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