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value::as_uint64 (2 of 2 overloads)

Return the underlying std::uint64_t, or throw an exception.

Synopsis
std::uint64_t
as_uint64() const;
Description

If is_uint64() is true, returns the underlying std::uint64_t, otherwise throws an exception.

Complexity

Constant.

Exception Safety

Strong guarantee.

Exceptions

Type

Thrown On

boost::system::system_error

! this->is_uint64().

Note

This function is the const-qualified overload of as_uint64, which is intended for direct access to the underlying object, if it has the type std::uint64_t. It does not convert the underlying object to type std::uint64_t even if a lossless conversion is possible. If you are not sure which kind your value has, and you only care about getting a std::uint64_t number, consider using to_number instead.


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