Boost
C++ Libraries
...one of the most highly
regarded and expertly designed C++ library projects in the
world.
— Herb Sutter and Andrei
Alexandrescu, C++
Coding Standards
Boost
C++ Libraries
...one of the most highly
regarded and expertly designed C++ library projects in the
world.
— Herb Sutter and Andrei
Alexandrescu, C++
Coding Standards
Return the underlying std::uint64_t,
or throw an exception.
std::uint64_t as_uint64() const;
If is_uint64()
is true, returns the underlying
std::uint64_t, otherwise throws an exception.
Constant.
Strong guarantee.
|
Type |
Thrown On |
|---|---|
|
|
|
This function is the const-qualified overload of as_uint64, which is intended
for direct access to the underlying object, if
it has the type std::uint64_t. It does not convert the underlying
object to type std::uint64_t even if a lossless conversion
is possible. If you are not sure which kind your value
has, and you only care about getting a std::uint64_t
number, consider using to_number instead.