...one of the most highly
regarded and expertly designed C++ library projects in the
world.

— Herb Sutter and Andrei
Alexandrescu, C++
Coding Standards

#include <boost/math/special_functions/factorials.hpp>

namespace boost{ namespace math{ template <class T> T double_factorial(unsigned i); template <class T, class Policy> T double_factorial(unsigned i, const Policy&); }} // namespaces

Returns `i!!`

.

The final Policy argument is optional and can be used to control the behaviour of the function: how it handles errors, what level of precision to use etc. Refer to the policy documentation for more details.

May return the result of overflow_error
if the result is too large to represent in type T. The implementation is
designed to be optimised for small *i* where table lookup
of i! is possible.

Important | |
---|---|

The functions described above are templates where the template argument T can not be deduced from the arguments passed to the function. Therefore if you write something like:
You will get a (possibly perplexing) compiler error, ususally indicating that there is no such function to be found. Instead you need to specifiy the return type explicity and write:
So that the return type is known. Further, the template argument must be
a real-valued type such as
The source code BOOST_STATIC_ASSERT(!boost::is_integral<T>::value); // factorial<unsigned int>(n) is not implemented // because it would overflow integral type T for too small n // to be useful. Use instead a floating-point type, // and convert to an unsigned type if essential, for example: // unsigned int nfac = static_cast<unsigned int>(factorial<double>(n)); // See factorial documentation for more detail. |

Note | |
---|---|

The argument to |

The implementation uses a trivial adaptation of the factorial function, so error rates should be no more than a couple of epsilon higher.

The spot tests for the double factorial use data generated by functions.wolfram.com.

The double factorial is implemented in terms of the factorial and gamma functions using the relations:

(2n)!! = 2^{n } * n!

(2n+1)!! = (2n+1)! / (2^{n } n!)

and

(2n-1)!! = Γ((2n+1)/2) * 2^{n } / sqrt(pi)